Answer:
C: 1 over 7 to the 2nd power
Step-by-step explanation:
The question is: [tex]7^{3} \times 7^{-5}[/tex]
When multiplying exponents, the base stays the same, while the power is added. In this question, the powers are 3 and -5.
[tex]3+-5=-2[/tex]
The exponent will become: [tex]7^{-2}[/tex]
Since the power is negative, it is improper. The negative can be removed by moving the power down and making it a fraction over 1.
[tex]7^{-2} \rightarrow \frac{1}{7^{2} }[/tex]
The answer is [tex]\frac{1}{7^{2}}[/tex], also written as "1 over 7 to the 2nd power".
