Answer:
15 units
Step-by-step explanation:
The distance between any two points (x1,y1) and (x2,y2) on a coordinate plane is given by [tex]\sqrt{(x1-x2)^2+ (y1-y2)^2}[/tex]
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for the problem given
points are C(-5,6) to D(4,-6)
Thus distance from c to D is explained below by substituting the value of point C and D is distance calculation formula given above
[tex]distance \ CD = \sqrt{(x1-x2)^2+ (y1-y2)^2}\\=>distance \ CD = \sqrt{(-5-4)^2+ (6-(-6)^2}\\=>distance \ CD = \sqrt{(-9)^2+ (6+6)^2}\\=>distance \ CD = \sqrt{81+ (12)^2}\\=>distance \ CD = \sqrt{81+ 144}\\=>distance \ CD = \sqrt{225}\\=>distance \ CD = \sqrt{15^2}\\=>distance \ CD = 15[/tex]
Thus, distance from C(-5,6) to D(4,-6) is 15 units.