Answer:500 W
Explanation:
Given
When length is L power dissipated is [tex]100\ W[/tex]
Potential difference applied is [tex]200\ V[/tex]
Resistance of wire is directly proportional to length of wire
Suppose initially Resistance is R
When L changes to [tex]2L[/tex]
Resistance changes to [tex]2R[/tex]
Initial Power dissipated is [tex]P_o=\frac{V^2}{R}[/tex]
For 2 R resistance and same voltage, Power dissipated is
[tex]P_1=\frac{V^2}{(2R)}[/tex]
So [tex]P_1=\frac{1}{2}\times \frac{V^2}{R}[/tex]
[tex]P_1=\frac{P_o}{2}[/tex]
So [tex]P_1=\frac{1000}{2}[/tex]
[tex]P_1=500\ W[/tex]
