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How many moles of lithium chloride will be formed by the reaction of chlorine with 0.046 mol of lithium bromide in the following reaction?

2LiBr(aq) + Cl2(g) → 2LiCl(aq) + Br2(l) ans: 0.046 mol LiCl

Respuesta :

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Answer:

The answer is 0.046 mol.

Explanation:

By looking at the balanced equation, you can form a ratio of lithium chloride and lithium bromide using the coefficient value :

ratio of lithium bromide (2LiBr)

= 2

ratio of lithium chloride (2LiCl)

= 2

So the ratio is 2 : 2 then simplify into 1 : 1 . Which means that 1 mol of lithium bromide is equal to 1 mole of lithium chloride.

In this case, 0.046 mol of lithium bromide will form 0.046 mol of lithium chloride.

The number of moles should be 0.046 mol.

Calculation of a number of moles:

Here we can create a ratio of lithium chloride and lithium bromide by applying the coefficient value :

the ratio of lithium bromide (2LiBr) = 2

And, the ratio of lithium chloride (2LiCl) = 2

Here 2:2 means 1:1

So, the number of moles should be the same i.e. 0.046 mol.

learn more about reaction here: https://brainly.com/question/13446507

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