What is the slope of the line through (-9,-6)(−9,−6)left parenthesis, minus, 9, comma, minus, 6, right parenthesis and (3,-9)(3,−9)left parenthesis, 3, comma, minus, 9, right parenthesis?

Respuesta :

Answer:

[tex]-\dfrac{1}{4}[/tex]

Step-by-step explanation:

Given two points (-9,-6) and (3,-9). The slope of the line through the points is determined by the formula:

[tex]Slope, m=\dfrac{y_2-y_1}{x_2-x_1} ,$ where (x_1,y_1)=(-9,-6), (x_2,y_2)=(3,-9)\\$Therefore:\\ m=\dfrac{-9-(-6)}{3-(-9)}\\=\dfrac{-9+6}{3+9}\\=\dfrac{-3}{12}\\\\m=-\dfrac{1}{4}\\[/tex]

The slope of the line through the points (-9,-6) and (3,-9) is [tex]-\dfrac{1}{4}[/tex]

Answer:

the slope of the line through the points (-9,-6) and (3,-9) is [tex]-\dfrac{1}{4}[/tex]

Step-by-step explanation:

Given that,

Points (x₁ , y₁) is (-9,-6) respectively and

( x₂ , y₂) is (3,-9) respectively.

The slope of the line through the points is determined by the formula:

[tex]Slope, m=\dfrac{y_2-y_1}{x_2-x_1}[/tex]

where x₁ = -9

y₁ = -6

x₂ = 3

y₂ = -9

Therefore:

[tex]\\ m=\dfrac{-9-(-6)}{3-(-9)}\\=\dfrac{-9+6}{3+9}\\=\dfrac{-3}{12}\\\\m=-\dfrac{1}{4}\\[/tex]

Therefore, the slope of the line through the points (-9,-6) and (3,-9) is [tex]-\dfrac{1}{4}[/tex]