Answer:
Explanation:
We shall apply time dilution relation of relativity
t = [tex]\frac{t_0}{\sqrt{1-\frac{v^2}{c^2} } }[/tex]
[tex]1000 = \frac{t_0}{\sqrt{1-\frac{v^2}{c^2} } }[/tex]
[tex]1000 = \frac{t_0}{\sqrt{1-\frac{0.995^2}{1} } }[/tex]
t₀ = 1000 x .09987
= 99.87 days .
doubling time = 20 days
no of doubling time in 20 days ; n = 99.87 / 20
n = 4.9935
n = [tex]n_0\times 2^n[/tex] ; n₀ is initial number , n is number finally .
= 2 x 2⁴°⁹⁹³⁵
= 64 approx .
