Respuesta :
Answer:
Adding the same value to both sides of an inequality does not change the solution set; Option A
Step-by-step explanation:
* Adding the same value to both sides of an inequality does not change the solution set *
There are exceptions to inequalities. It is known that when dividing or multiplying negative numbers on either side of the sign, the sign is interchanged. This, keep in mind, it the only exception.
Options C and D state that: When dividing both sides of an inequality by the same positive value, it is necessary to reverse the inequality sign, and When multiplying both sides of an inequality by the same negative value, it is not necessary to reverse the inequality sign. It is convenient enough that these options dodge the rule, when multiplying/dividing by a positive value there is no change, and when multiplying/diving by a negative number the sign is reversed.
This leaves us with Options A and B. Option B states a difference made when subtracting two values, but there is no such exception. Option A states the exact opposite, that no difference is made when adding two values, which is true as the only exception is through multiplication and division of a negative value.
Adding the same value to both sides of an inequality does not change the solution set.
An inequality is a relationship that compares two numbers or other mathematical expressions in an unequal way. It is most commonly used to compare two numbers on a number line based on their size.
Adding the same value to both sides of an inequality does not change the solution set.
Subtracting the same value from both sides of an inequality does not change the solution set.
When dividing both sides of an inequality by the same positive value, it does not change the inequality sign.
When multiplying both sides of an inequality by the same negative value, the inequality sign changes.
So, correct option is "Adding the same value to both sides of an inequality does not change the solution set."
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https://brainly.com/question/11612965?referrer=searchResults
