Respuesta :
Answer:
The banking angle of the road is 16.38 degrees.
Explanation:
Given:
Radius of the roadway on curve, R = 50 m
velocity of the moving car, V = 12 m/s
The banking angle can be calculated by using the formula below:
If there's no frictional force, then net force is equal to centripetal force.
MgTanΦ = (MV^2)/ R
TanΦ = V^2 / gR
Where;
Φ is the banking angle
g is acceleration due to gravity
TanΦ = (12 x 12) / (9.8 x 50)
TanΦ = 0.2939
Φ = arctan (0.2939)
Φ = 16.38 degrees
Therefore, the banking angle of the road is 16.38 degrees.
The angle at which the road should be banked on the curve without reliance on friction should be 16.38°.
Given the Parameters :
- Radius, r = 50 m
- Velocity, V = 12 m/s
- Acceleration due to gravity constant, g = 9.8 m/s²
To avoid reliance on friction, such that, frictional force = 0 ; the angular position of the roadway could be obtained using the centripetal relation :
- [tex] \theta = tan^{-1} \frac{v^{2}}{rg} [/tex]
Substituting the parameters into the equation :
- [tex] \theta = tan^{-1} \frac{12^{2}}{50 \times9.8} [/tex]
- [tex] \theta = tan^{-1} \frac{144}{490} [/tex]
- [tex] \theta = tan^{-1} (0.2938775) = 16.376[/tex]
Therefore, the roadway on the curve should be banked at angle of 16.38°.
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