A scientist has two solutions, which she has labeled Solution A and Solution B. Each contains salt. She knows that Solution A is
40
%

salt and Solution B is
65
%

salt. She wants to obtain
40

ounces of a mixture that is
60
%

salt. How many ounces of each solution should she use?

Respuesta :

Answer:

We need 8 ounces of solution A and 32 ounces of solution B.

Step-by-step explanation:

We are given that a scientist has two solutions, which she has labeled Solution A and Solution B. Each contains salt.

She knows that Solution A is  40%  salt and Solution B is 65%  salt.

  • First condition states that she wants to obtain  40  ounces of a mixture that is  60 %  salt, that means;

                       A + B = 40

                        B = 40 - A  ------------ [Equation 1]

  • Second condition states that Solution A is  40%  salt and Solution B is 65%  salt, that means;

                        [tex]0.4 \text{A}+0.65 \text{B}=0.60 \times 40[/tex]

                        [tex]0.4 \text{A}+0.65 \text{B}=24[/tex]

                        [tex]0.4 \text{A}+0.65 (40- \text{A})=24[/tex]     {from equation 1}

                        [tex]0.4 \text{A}+26- \text{0.65A}=24[/tex]

                        [tex]\text{0.65A} - 0.4 \text{A}=26-24[/tex]

                                  [tex]\text{0.25A} =2[/tex]  

                                    A  =  [tex]\frac{2}{0.25}[/tex] = 8 ounces

Now, putting value of A in equation 1, we get;

                           B = 40 - A

                           B = 40 - 8 = 32 ounces

Hence, we need 8 ounces of solution A and 32 ounces of solution B.