What is the following quotient? StartFraction 3 StartRoot 8 EndRoot Over 4 StartRoot 6 EndRoot EndFraction StartFraction 12 StartRoot 2 EndRoot minus 6 StartRoot 3 EndRoot Over 5 EndFraction StartFraction 3 StartRoot 6 EndRoot minus 4 StartRoot 3 EndRoot Over 24 EndFraction StartFraction StartRoot 3 EndRoot Over 12 EndFraction StartFraction StartRoot 3 EndRoot Over 2 EndFraction

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Answer:

the answer is D

The quotient of the given function is [tex]\frac{\sqrt{3}}{2}[/tex]

Given the radical function

  • [tex]\dfrac{3\sqrt{8} }{4\sqrt{6} }[/tex]

Rationalizing the denominator:

[tex]= \dfrac{3\sqrt{8} }{4\sqrt{6} } \times \dfrac{\sqrt{6} }{\sqrt{6} }\\= \dfrac{3\sqrt{8} (\sqrt{6}) }{4\sqrt{6} \cdot \sqrt{6}}\\[/tex]

Multiplying the numerator and denominator:

[tex]=\dfrac{3\sqrt {48}}{4(6)} \\=\dfrac{3(4\sqrt{3})}{24} \\=\dfrac{4\sqrt{3}}{8} \\=\dfrac{\sqrt{3}}{2}[/tex]

Hence the quotient of the given function is [tex]\frac{\sqrt{3}}{2}[/tex]

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