In some cattle, the genes for brown hair and for white hair are codominant. Cattle with
alleles for both brown and white hair have both brown and white hairs. This condition gives the cattle a reddish color, and is referred to as roan. If a roan bull is bred with a white cow, what is the probability of them having a roan offspring?
A: 0/4
B: 1/4
C: 1/2
D: 3/4

This question involves a single gene coding for hair color in some cattle. The allele for brown hair (B) is codominant with the allele for white hair (W). This means that they are both expressed in the hybrid/heterozygous state (BW) to give a reddish-colored cattle called ROAN.

This means that a brown and white cattle will both be homozygous with same alleles; BB and WW for brown and white respectively.

According to the question, if a roan bull (BW) is crossed with a white cow (WW), each cattle will produce gametes as follows:

BW- B and W

WW- W and W

Using these gametes in a punnet square (see attached image), 4 possible offsprings will be produced with a genotypic ratio: BW (2) : WW (2)

BW (2) offsprings are roan

WW (2) offsprings are white

Hence, the probability of producing a roan offspring (BW) from this cross is 2/4 or 1/2.

JackelineCasarez JackelineCasarez · Answer 2 · 2022-04-12T18:47:06+02:00

The probability of possessing a roan offspring would be as follows:

C). 1/2

Genotypic Ratio

What information do we have:

Single code of a gene and having allele through brown hair(B) remaining codominant and white hair(w) allele.

Thus, they can be denoted as being in a hybrid state i.e. BW, and develop ROAN i.e. red in color.

This implies that brown, as well as, white cattle would remain both alleles through the same alleles i.e. BB and WW.

Using this, we can find the genotypic ratio:

= favorable offspring/total offspring

= 2/4

= 1/2

Therefore, the probability of generating a roan offspring (BW) using this cross would be 2/4 or 1/2.

Learn more about "Probability" here:

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