Respuesta :
Answer:
40 more paintings in order to maximize sales making a total of 60 paintings
Step-by-step explanation:
Let x= no.of copies above 20
Total Sales(x) = (number of copies)(price per copy)
Sales (x)= (20 +x)(100 –x)
Open bracket
=1200-20x+100x-x^2
=1200+80x-x^2
Derivative of the sales
80-2x=0
80=2x
Divide both sides by 2
40=x
Because Sales(x)= –2, this is maximal by the second derivative test
The artist should make 40 more paintings in order to maximize sales making a total of 60 paintings.
The artist 60 copies should he make to maximize his sales
The artist can sell 20 copies at $100 each.
So, the total sales is:
Total =(20) * (100)
For each additional copy he makes, the value of each painting reduce by a dollar.
So, the total sales becomes
Total = (20 + x) * (100 - x)
Rewrite as:
[tex]y = (20 + x) * (100 - x)[/tex]
Expand
[tex]y = 2000 - 20x + 100x - x^2[/tex]
Evaluate the like terms
[tex]y = 2000 +80x - x^2[/tex]
Differentiate
[tex]y' = 80 - 2x[/tex]
Set to 0
[tex]80 - 2x = 0[/tex]
Collect like terms
[tex]- 2x = -80[/tex]
Divide both sides by -2
[tex]x = 40[/tex]
Recall that the initial copies is 20.
So, the new copies would be:
New = 20 + 40
New = 60
Hence, the artist 60 copies should he make to maximize his sales
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