Answer:
326 ft
Step-by-step explanation:
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Maribel a b Karl
[tex] \tan 25^\circ = \dfrac{125~ft}{a} [/tex]
[tex] a \tan 25^\circ = 125~ft [/tex]
[tex] a = \dfrac{125~ft}{\tan 25^\circ} [/tex]
[tex] a = 268~ft [/tex]
[tex] \tan 65^\circ = \dfrac{125~ft}{b} [/tex]
[tex] b \tan 65^\circ = 125~ft [/tex]
[tex] b = \dfrac{125~ft}{\tan 65^\circ} [/tex]
[tex] b = 58~ft [/tex]
[tex] distance = a + b = 268~ft + 58~ft = 326~ft [/tex]
