Given
m10C is a straight angle
m / BOC=629
mZAOB
= 3.7 +124°
Find mZBOG:
1
о
o

Answer:
83 degrees
Step-by-step explanation:
<BOC + <AOB = 180
<BOC= 180-<AOB [ angles on a straight line is 180degrees]
6x + 29 =180 -(3x + 124)
6x + 29 = 180-124 -3x
6x-3x= 56 -29
3x= 27
x = 9
Therefore:
<BOC =6x + 29 = 6( 9) + 29 = 54 + 29 = 83 degrees