We have been given that Steph places a point on a coordinate plane at (3, -2). She wants to place another point across the x-axis, and it must be 7 units away. We are asked to find the point, where Steph will place it.
Since the point will be across x-axis, so x-coordinate of of other point will be same that is 3.
Now we will use distance formula to find the coordinate of other point.
[tex]D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
[tex]7=\sqrt{(3-3)^2+(y-(-2))^2}[/tex]
[tex]7=\sqrt{0+(y+2)^2}[/tex]
[tex]7=\sqrt{(y+2)^2}[/tex]
Square root will cancel out with square.
[tex]7=y+2[/tex]
[tex]7-2=y+2-2[/tex]
[tex]5=y[/tex]
Therefore, the Steph will point the other point at [tex](3,5)[/tex].
