Answer:
Step-by-step explanation:
This is a normal distribution question with
Mean = 153
Standard Deviation= 10
Since we know that score
[tex]Z_{score}=\frac{x- \mu}{ \sigma }[/tex]
a)
P(x > 150.0)=?
The z-score at x = 150.0 is,
[tex]Z = \frac{150-153}{10} \\\\Z=-0.3[/tex]
This implies that
P(x > 150.0) = P(z > -0.3)
= 1 - P(z < -0.3) = 1 - 0.3820885778110474
P(x > 150) = 0.6179
