Respuesta :

wagnere082

Answer:

5

Step-by-step explanation:

Finding the distance, midpoint, slope, equation and the x y-intercepts of a line passing between the two points p1 (7,6) and p2 (2,6)

The distance (d) between two points (x1,y1) and (x2,y2) is given by the formula

d= √((X2-X1)2+(Y2-Y1)2)

d = √(2-7)2+(6-6)2

d = √((-5)2+(0)2)

d= √(25+0)

d = √25

The distance between the points is 5

jzonfleek016

Step-by-step explanation:

[tex]Distance(d)=\sqrt{(x2-x1)^2+(y2-y1)^2}[/tex]

Now, we add in our coordinates to their respectful places and simplify the radical.

[tex]d=\sqrt{(7-2)^2+(6-6)^2}\\ d=\sqrt{(5)^2+(0)^2} \\d=\sqrt{25+0}\\ d=\sqrt{25}\\ d=5[/tex]

So the distance from (2,6) and (7,6) is 5 units.

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