[tex] \measuredangle BAC = 29°[/tex]
Answer:
[tex] \measuredangle BOC =58°[/tex]
Step-by-step explanation:
[tex] \measuredangle BDC = 29°...(Given) \\
\because \measuredangle BAC = \measuredangle BDC\\(\angle 's \: subtended \: by\: same\: arc) \\
\huge \purple {\boxed {\therefore \measuredangle BAC = 29°}} \\\\[/tex]
Since, angle subtended on the center of the circle is twice the angle subtended on the circumference of the circle.
[tex] \therefore \measuredangle BOC =2\times \measuredangle BDC\\
\therefore \measuredangle BOC =2\times 29°\\
\huge \red {\boxed {\therefore \measuredangle BOC =58°}} \\[/tex]
