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5. Find the center and radius of the circle with the given equation.
(x + 4)^2 + (y - 1)^2 = 25
A) Center(-4,1); r = 5
B) Center(4, -1); r = 5
C) Center(-4,1); r = 25
D) Center(4, -1); r = 25

5 Find the center and radius of the circle with the given equation x 42 y 12 25 A Center41 r 5 B Center4 1 r 5 C Center41 r 25 D Center4 1 r 25 class=

Respuesta :

Answer:

A

Step-by-step explanation:

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k) are the coordinates of the centre and r is the radius

(x + 4)² + (y - 1)² = 25 ← is in standard form

with centre = (- 4, 1 ) and r = [tex]\sqrt{25}[/tex] = 5 → A

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