Answer:
D = 320 m
Explanation:
Initial speed of the car is 0 as it was at rest.
Acceleration of the car along x axis is 5 m/s² for 8 seconds
Let d is the distance covered by the car in first 8 seconds. So,
[tex]d=ut+\dfrac{1}{2}at^2\\\\d=\dfrac{1}{2}\times 5\times 8^2\\\\d=160\ m[/tex]
The velocity attained in 8 seconds is given by :
[tex]v=u+at\\\\v=5\times 8\\\\v=40\ m/s[/tex]
Let d' is the distance covered by the car in next 4 seconds. So,
[tex]d'=40\times 4=160\ m[/tex]
Total distance covered by the car is :
D = d +d'
D= 160 m + 160 m
D = 320 m
So, the car will cover a distance of 320 m since it started from the rest.
