Respuesta :
Answer:
Check below
Step-by-step explanation:
With the information given, let's consider some aspects of Sandy Beach behavior.
1. Sandy Beach
Let's calculate the period of this function
[tex]t=4sin(s)+5[/tex]
[tex]T=\frac{2\pi}{b} \:b=1 \:in \:this \:case[/tex]
[tex]T=\frac{2\pi}{1} \therefore T= 2\pi[/tex]
The Period of sin function is [tex]2\pi[/tex]
2. Verifying the Range, in this case the lapse of time.
A sin function varies from -1 to 1, i.e.
[tex]-1\leq sin(s) \leq1 \therefore-4\leq 4sin(s)\leq4 \\ adding \:the\:5\\-4+5\leq 4sin(s)\leq4+5\\\\\1\leq4sin+5\leq9 \therefore t=[1,9]\\[/tex]
So, within an interval form 1 to 9 hours the waves at Sandy Beach come and go.
3. Check the graph below.
