Respuesta :

jbferrado

Answer:

The correct answer is 0.25 moles NH₃

Explanation:

First, we need to know the chemical equation for NH₃ formation from H₂. The balanced chemical reaction involved in NH₃ obtention is the following:

N₂(g) + 3 H₂(g) → 2 NH₃(g)

According to this, 2 moles of NH₃ are formed from 3 moles of H₂. We can write that estequiometrical relation as: 2 moles NH₃/ 3 moles H₂.

From the problem, we have to calculate how many moles of NH₃ are produced from 0.37 moles H₂. So, we can simply multiply the number of moles of H₂ to obtain by the convertion factor:

0.37 moles H₂ x 2 moles NH₃/ 3 moles H₂= 0.246 moles NH₃ ≅ 0.25 moles NH₃

Thus, 0.25 moles of NH₃ will be obtained.

sebassandin

Answer:

[tex]n_{NH_3}=0.25molNH_3[/tex]

Explanation:

Hello,

In this case, the undergoing chemical reaction should be:

[tex]3H_2+N_2\rightarrow 2NH_3[/tex]

Thus, since 0.37 moles of hydrogen are reacting, by using its 3:2 molar ratio with ammonia (NH3), we can compute the produced moles of NH3 as shown below:

[tex]n_{NH_3}=0.37molH_2 *\frac{2molNH_3}{3molH_2} \\\\n_{NH_3}=0.25molNH_3[/tex]

Best regards.

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