Answer:
Explanation:
We determine the weight of CaO and Na₂O by setting two simultaneous equation with the two unknown as follows
[tex]17=\frac{100a}{100+a+b} ---(1)[/tex]
[tex]5=\frac{1000b}{100+a+b}---(2)[/tex]
a and b represent Na₂O and CaO respectively.
By solving you get
a = 23.8
b = 16.2
We will calculate the molecular weight of Na₂CO₃ and Na₂O
Na₂CO₃ = 2(22.99) + 12.01 + 3(16)
= 105.99 g / mol
Na₂O = 2(22.99) + 16
= 61.98g / mol
We can now find the mass by taking the weight of Na₂O and multiple it by fraction of molar weight
[tex]= 23.8 \times \frac{105.99}{61.98} \\\\=40.71lb[/tex]
Similarly, We will calculate the molecular weight of CaCO₃ and CaO
CaCO₃ = 40.08 + 12.0+ 3(16)
= 100.09g/mol
CaO = 40.08 + 16
= 56.08 g / mol
We can now find the mass by taking the weight of CaCO₃ and multiple it by fraction of molar weight
[tex]=16.2 \times \frac{100.09}{56.08} \\\\=28.9lb[/tex]
therefore, the answer = 40.7lb and 28.9lb
