Answer: [-π/2, π/2]
Step-by-step explanation: The range of [tex]y=sin^-^1x[/tex] is actually equal to the domain of y=sin x, but it wouldn't be a function, according to the definition of a function. But if you restrict the range, it becomes a one-to-one function.
The range of the function y = sin ⁻¹x is (-1,1 )
The range of a function is all the possible value a function can have.
The function given is
y = sin ⁻¹x
The domain of the function is [ -π/2 ,π/2]
The range is therefore ( -1, 1)
The sin x function is not a one to one function but as the domain of the function is restricted of the inverse function , it behaves as a one to one function.
It can also be seen in the graph attached with the answer.
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