In squirrels, bushy tail (B) is dominant to smooth tail (b), and gray coat (G) is dominant to brown coat (g). These two loci are linked. Pure-breeding gray, smooth-tailed squirrels were mated to pure-breeding brown, bushy-tailed squirrels. The F1 were testcrossed. Testcross progeny consisted of 278 gray, smooth-tailed, 24 gray, bushy-tailed, 306 brown, bushy-tailed, and 35 brown, smooth-tailed squirrels. Calculate the map distance between these two genes in centimorgans. Round your answer properly to 2 decimal digits. Type in only the numerical value for your map distance without indicating the units.

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Answer:

The percentage of recombinants = (59/643) ×100 = 9.1%. Thus, the two genes are 9.1 mu or 9.1 cm apart.

The percentage of palatals = (584/643) ×100 = 9.1%. Thus, the two genes are 90.8 mu or 90.8 cm apart.

Explanation:

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