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TheAnimeGirl

[tex]\\ solution \\ hypotenuse = 13 \: cm \\ perpendicular = 5 \: cm \\ base = 12 \: cm \\ now \\ using \: pythagorus \: theorem \\ {h}^{2} = {p}^{2} + {b}^{2} \\ or \: {13}^{2} = {5}^{2} + {12}^{2} \\ or \: {13}^{2} = 25 + 144 \\ or \: {13}^{2} = 169 \\ or \: 13 \times 13 = 169 \\ 169 = 169 \\ so \: it \: is \: proved \: that \: angle \: a \: must \\ be \: right \: angle. \\ hope \: it \: helps..[/tex]

Hi1315

Answer with step by step explanation.

hypotenuse (h) = 13

perpendicular (p) = 5

base (b) = 12

Let's use the Pythagorean theorem

[tex] {h}^{2} = {p}^{2} + {b}^{2} \\ {13}^{2} = {5}^{2} + {12}^{2} \\ 169 = 25 + 144 \\ 169 = 169[/tex]

we proved that this is a right angle triangle.

hope this helps

brainliest appreciated

good luck! have a nice day!

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