Answer:
[see below]
For "slope-point" form:
Slope point (also called "Point-slope") form is: [tex]y-y_1=m(x-x_1)[/tex]
[tex](x_1,y_1)\text{ -Coordinate} \\m\text{ -Slope}[/tex]
Finding the Slope:
We need to find the slope of the line given.
Slope is: [tex]m=\frac{y2_-y1}{x_2-x_1}[/tex]
We are given the points (2,-1) and (-2,-2).
[tex]m=\frac{-2-(-1)}{-2-2}=\frac{-1}{-4}=\boxed{\frac{1}{4}}[/tex]
The slope of the line is 1/4.
Creating the Point-Slope Equation:
Replace 'm' with 1/4 and '(x1, y1)' with (2, -1).
[tex]y-y_1=m(x-x_1)\rightarrow\boxed{y+1=\frac{1}{4}(x-2)}[/tex]
[tex]\text{The equation of the graphed line in slope-point form using (2,-1) is:}\\y+1=\frac{1}{4}(x-2)[/tex]
Creating the Slope Intercept Form Equation:
Slope intercept form is: [tex]y=mx+b[/tex]
We can convert our point slope equation into slope intercept form.
[tex]y+1=1/4(x-2)\\\\y+1=1/4x-0.5 \leftarrow \text{Distribute}\\y+1-1=1/4x-0.5-1 \leftarrow \text{Subtraction Property of Equality}\\\boxed{y=\frac{1}{4}x-1.5}[/tex]
The equation of the line in slope intercept form is: [tex]y=\frac{1}{4}x-1.5[/tex] OR [tex]y=\frac{1}{4}x-\frac{3}{2}[/tex].
