What is the equation, in point-slope form, for a line that goes through(8,
4) and has a slope of - 5/6?
oy-4--5 (x+8)
Oy-4--5 (2-8)
O y+4= -5 (0-8)
O y+4= -= (2+8)

Respuesta :

Answer:

[tex]\boxed{y-4=-\frac{5}{6}(x-8)}[/tex]

Step-by-step explanation:

Point slope form is: [tex]y-y_1=m(x-x_1)[/tex]

[tex](x_1,y_1) - Coordinate\\ m- Slope[/tex]

We are given the slope of [tex]-\frac{5}{6}[/tex] and the point of (8,4).

Replace 'm' with -5/6, 'x1' with 8, and 'y1' with 4.

[tex]y-y_1=m(x-x_1)\rightarrow \boxed{y-4=-\frac{5}{6}(x-8)}[/tex]

I do not see any options that match this, but the boxed equation should the correct answer.