Answer:
( - 3, - 1 ), ( 3, - 1 ) / ( - 3, 11 ), ( 3, 11 )
Step-by-step explanation:
Let us first consider the distance between points ( - 3, 5 ) and ( 3, 5 );
[tex]( - 3, 5 ), ( 3, 5 )\\Distance = 3 + 3 = 6 units[/tex]
If these are points that are vertices of the square, it should be that the other 2 points are 6 units farther from these points;
[tex]Distance = 6 units,\\( - 3, 5 ) - ( - 3, - 1 )\\( 3, 5 ) - ( 3, - 1 )[/tex]
[tex]Distance = 6 units,\\( -3, 5 ) - ( - 3, 11 )\\( 3, 5 ) - ( 3, 11 )[/tex]
Let us confirm ( -3, - 1 ) and ( 3, - 1 ) are 6 units apart, respectively ( -3, 11 ) and ( 3, 11 ) to say they are the other two vertices;
[tex]( - 3, - 1 ), ( 3, - 1 )\\Distance = 3 + 3 = 6 units[/tex]
[tex]( -3, 11 ), ( 3, 11 )\\Distance = 3 + 3 = 6 units[/tex]
Thus, the possible vertices are ( - 3, - 1 ) and ( 3, - 1 ) or ( - 3, 11 ) and ( 3, 11 )
