Respuesta :
Answer:
- 4.8195 g; $2.36
- 1.0389; sink in water
Explanation:
1a. 85% of 5.670 g is ...
0.85 × 5.670 g = 4.8195 g . . . . mass of silver
1b. The value of that will be ...
(4.8195 g)($0.49/g) ≈ $2.36 . . . . value of silver in a pre-1955 quarter
__
2. 1 pound is 453.59237 g (exactly), so the density of the peanut butter is ...
density = mass/volume = (453.59237 g)/(436.6 cm^3)
density ≈ 1.0389 g/cm^3
We expect this peanut butter to sink in water, as its density is more than the 1.00 g/cm^3 density of water.
1.
- The value of the silver in the quarter is $2.36.
- The mass of silver in quater is 4.1895 grams,
2.
- The density of peanut butter is [tex]1.039 g/cm^3[/tex]
- The peanut butter will sink in water.
Given:
1) Mass of pre-1955 quarter is 5.670g, 85% of silver by mass.
Silver is currently valued at $0.49 per gram.
2) A 1-lb jar of peanut butter is found to have a volume of [tex]436.6 cm^3[/tex]
To find:
Mass of silver in pre-1955 quarter
The value of silver in quarter
Density of the peanut butter
Whether peanut buter will float or sink in water.
Solution:
1) Mass of pre-1955 quarter = 5.670g
The percentage of the silver in the quarter =85%
Mass of silver in pre-1955 quarter= [tex]5.670 \times \frac{85}{100}=4.8195 g[/tex]
The mass of silver in quater is 4.1895 grams,
The current value of the silver = $0.49 per gram g
The value of silver in quarter :
[tex]=4.8195 g\times 0.49 \$/g=\$2.36[/tex]
The value of the silver in the quarter is $2.36.
2)
The mass of peanut butter in jar = m = 1 lb = 453.592 g
The volume of peanut butter in the jar = v = [tex]436.6 cm^3[/tex]
The density of the peanut jar = d
[tex]d=\frac{m}{v}\\\\=\frac{453.592 g}{436.6 cm^3}=1.039 g/cm^3[/tex]
The density of peanut butter is [tex]1.039 g/cm^3[/tex]
The density of the water = D = [tex]1 g/cm^3[/tex]
d > D
The density of peanut butter is greater than density of water which indicates that peanut butter will sink in water.
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