Answer:
8.1×10^-8 mols-1
Explanation:
Now we have the mass of copper sulphate produced after three days. Recall that the rate of reaction is given as;
Rate= change in the concentration of product/time
At the beginning of the reaction, there was 0 moles of copper sulphate
After 72 hours or 259200 seconds, there was 3.4g/160gmol-1 = 0.021 moles of copper sulphate.
Note that 160gmol-1 is the molar mass of copper sulphate.
Hence;
Rate of reaction= 0.021 moles /259200 seconds
Hence, the rate of reaction is 8.1×10^-8 mols-1
Rate of reaction= 8.1×10^-8 mols-1
