Answer:
d. 0.9 mol
Explanation:
On this case we have to start with the formula of acetylene:
[tex]C_2H_2[/tex]
Now we can write the chemical reaction of combustion:
[tex]C_2H_2~+~O_2~->~CO_2~+~H_2O[/tex]
The next step is to balance the reaction:
[tex]2C_2H_2~+~5O_2~->~4CO_2~+~2H_2O[/tex]
The molar ratio between [tex]C_2H_2[/tex] and [tex]CO_2[/tex] is 2:4, so:
[tex]0.3~mol~C_2_H_2\frac{4~mol~CO_2}{2~mol~C_2H_2}=0.6~mol~CO_2[/tex]
The molar ratio between [tex]C_2H_2[/tex] and [tex]H_2O[/tex] is 2:2, so:
[tex]0.3~mol~C_2_H_2\frac{2~mol~H_2O}{2~mol~C_2H_2}=0.3~mol~H_2O[/tex]
The total moles would 0.6 + 0.3=0.9 moles.
I hope it helps!
