Answer:
The equation for the new line in slope-intercept form is:
[tex]y=4x+2[/tex]
Step-by-step explanation:
Since they give us an equation in slope-intercept form "y=4x+5", it is easy to extract the slope the new parallel line to this should have : "4" (same slope as the reference line)
We are also given a point the new line should go through : "(1, 6)"
So we can use the "point-slope" form of a line to find the equation of this new line:
[tex]y-y_0=m(x=x_0)\\y=m(x-x_0)+y_0[/tex]
which for our case is:
[tex]y=m(x-x_0)+y_0\\y=4\,(x-1)+6\\y=4x-4+6\\y=4x+2[/tex]
