Answer:
a ) - 8x^7,
b ) - 4m^2 / nx,
c ) - 11a^2b^18 / 5
Step-by-step explanation:
[tex]a ) (2x^2)(-4x^5),\\-2x^2\cdot \:4x^5,\\-8x^5x^2,\\-8x^7\\\\Solution = -8x^7[/tex]
To solve this problem, I removed ( ), multiplied the terms, and through the " exponential rule " added the exponents to derive the solution - 8x^7
[tex]b ) (36m^2) / (-9nx),\\-\frac{36m^2}{9nx},\\-\frac{4m^2}{nx}\\\\Solution = -\frac{4m^2}{nx}[/tex]
Here I simplified the bit " 36 / 9 " which was found as 4 in the numerator, deriving the solution - 4m^2 / nx
[tex]c ) -11ab^9b^6 / 5b^3a,\\-11b^9\frac{b^6}{5}b^3a^{1+1},\\-11b^9\frac{b^6}{5}b^3a^2,\\-11\cdot \frac{b^6}{5}b^{9+3}a^2,\\-11\cdot \frac{b^6}{5}b^{12}a^2,\\-\frac{b^6\cdot \:11b^{12}a^2}{5},\\-\frac{11a^2b^{18}}{5},\\\\Solution = -\frac{11a^2b^{18}}{5}[/tex]
I applied a combination of " the exponential rule " and the addition of these exponents to receive a simplified solution - 11a^2b^18 / 5.
