Answer:
The problem provides you with the solubility of potassium chloride,
KCl
, in water at
20
∘
C
, which is said to be equal to
34 g / 100 g H
2
O
.
This means that at
20
∘
C
, a saturated solution of potassium chloride will contain
34 g
of dissolved salt for every
100 g
of water.
As you know, a saturated solution is a solution that holds the maximum amount of dissolved salt. Adding more solid to a saturated solution will cause the solid to remain undissolved.
In your case, you can create a saturated solution of potassium chloride by dissolving
34 g
of salt in
100 g
of water at
20
∘
C
.
Now, your goal here is to figure out how much potassium chloride can be dissolved in
300 g
of water at this temperature. To do that, use the given solubility as a conversion factor to take you from grams of salt to grams of water
300
g H
2
O
⋅
34 g KCl
100
g H
2
O
=
102 g KCl
You should round this off to one sig fig, since that is how many sig figs you have for the mass of water
∣
∣
∣
∣
¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯
a
a
mass of KCl
=
100 g
a
a
∣
∣
−−−−−−−−−−−−−−−−−−−−−−−
Explanation:
Based on the solubility curve, 27.2 g of KCl will dissolve in 68.0 g of water.
A solubility curve is a curve which plots the amount of solute that can dissolve in a given volume of solvent against changes in temperature.
The solubility of a gives the amount that of solute that can dissolve in a given volume of solvent at a given temperature.
Based on the solubility curve above, 40 grams of potassium chloride (KCl) can be dissolved in 100.0g of water at 40°C.
Solubility of KCl at 40 °C = 0.4 g/g of water
Mass of KCl that can dissolve in 68.0 g of water = 0.4 × 68 = 27.2 g
Therefore, 27.2 g of KCl will dissolve in 68.0 g of water.
Learn more about solubility curve at: https://brainly.com/question/14366471
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