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Sick computers: Let V be the event that a computer contains a virus, and let W be the event that a computer contains a worm. Suppose
P(V) = 0.47, P(W) = 0.37, P(Vand W) = 0.01
(a) Find the probability that the computer contains either a virus or a worm or both.
(b) Find the probability that the computer does not contain a worm
Part 1 of 2
(a) Find the probability that the computer contains either a virus or a worm or both.
The probability that the computer contains either a virus or a worm or both is
Х
5
Part 2 of 2
(b) Find the probability that the computer does not contain a worm
The probability that the computer does not contain a worm is
Х

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MathPhys

Answer:

0.83

0.63

Step-by-step explanation:

P(V or W) = P(V) + P(W) − P(V and W)

P(V or W) = 0.47 + 0.37 − 0.01

P(V or W) = 0.83

P(not W) = 1 − P(W)

P(not W) = 1 − 0.37

P(not W) = 0.63

a. the probability that the computer contains either a virus or a worm or both is 0.83

b. The probability that the computer does not contain a worm is 0.63.

Calculation:

(a)

The probability is

P(V or W) = P(V) + P(W) − P(V and W)

P(V or W) = 0.47 + 0.37 − 0.01

P(V or W) = 0.83

(b) The probability is

P(not W) = 1 − P(W)

P(not W) = 1 − 0.37

P(not W) = 0.63

Learn more about the probability here: https://brainly.com/question/16096170

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