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A 20 mL volume of a hydrochloric acid solution, HCl (aq), was placed into a beaker containing an appropriate
acid-base indicator. It was titrated with a solution of sodium hydroxide, NaOH (aq), until the endpoint was
reached. If 25 mL of sodium hydroxide solution with a concentration of 0.20 mol/L was used, what is the
concentration of the acid?
Select one:
a. 2.5 mol/L
O
b. 0.20 mol/L
C. 0.25 mol/L
d. 2.0 mol/L​

Respuesta :

barakaodoyo5

Answer:

C- 0.25mol/L

Explanation:

Hcl+Naoh-Nacl+H2O

Ratio =1:1

0.2moles of Naoh in1000cm3 what about 25=(25×0.2)÷1000=

0.005moles

0.005moles in 20cm³ what about in 1000

(0.005×1000)÷20=0.25mol/L

onukajoboy27

Answer:

c. 0.25mol/L

Explanation:

C1V1=C2V2

C1=C2V2/V1

(0.20mol/L)(0.025L)/0.02L

=0.25mol/L HCL

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