Answer:
F=265.39N
Explanation:
In order to solve this problem, we must first draw a diagram of what the problem looks like (see attached picture).
So, in order to find the torque we must use the torque formula:
[tex]\tau=rxF[/tex]
or
[tex]\tau=rFsin\theta[/tex]
In this case we can either use 125° or 55°, the answer should be the same. So when solving the formula for F we get:
[tex]F=\frac{\tau}{r sin\theta}[/tex]
so we can now substitute values:
[tex]F=\frac{50Nm}{(23x10^{-2}m)sin 125^{o}}[/tex]
so
F=265.39N