Answer:
Explanation:
Calculate the volume of the lead
[tex]V=\frac{m}{d}\\\\=\frac{10g}{11.3g'cm^3}[/tex]
Now calculate the bouyant force acting on the lead
[tex]F_L = Vpg[/tex]
[tex]F_L=(\frac{10g}{11.3g/cm^3} )(1g/cm^3)(9.8m/s^2)\\\\=8.673\times 10^{-3}N[/tex]
This force will act in upward direction
Gravitational force on the lead due to its mass will act in downward direction
Hence the difference of this two force
[tex]T=mg-F_L\\\\=(10\times10^{-3}kg(9.8m/s^2)-8.673\times 10^{-3}\\\\=8.933\times10^{-3}N[/tex]
If V is the volume submerged in the water then bouyant force on the bobber is
[tex]F_B=V'pg[/tex]
Equate bouyant force with the tension and gravitational force
[tex]F_B=T_mg\\\\V'pg=\frac{(8.933\times10^{-2}N)+mg}{pg} \\\\V'=\frac{(8.933\times10^{-2}N)+mg}{pg}[/tex]
Now Total volume of bobble is
[tex]\frac{V'}{V^B} =\frac{\frac{(8.933\times10^{-2})+Mg}{pg} }{\frac{4}{3} \pi R^3 }\times100\\\\=\frac{\frac{(8.933\times10^{-2})+(3)(9.8)}{(1000)(9.8)} }{\frac{4}{3} \pi (4.0\times10^{-2})^3 }\times100\\\\[/tex]
=[tex]\large\boxed{4.52 \%}[/tex]
