Answer:
The number of electrons removed is [tex]N = 9.513 *10^{11}[/tex]
Explanation:
From hr question we are told that
The radius is [tex]r = 0.193 \ m[/tex]
The required electrical potential is [tex]V = 7.10 \ kV = 7.10 *10^{3} V[/tex]
The total charge on the sphere is mathematically evaluated as
[tex]Q = \frac{Vr}{k}[/tex]
where k is the coulombs constant with value [tex]k =9)*10^{9} \ kg\cdot m^3\cdot s^{-4}\cdot A^2.[/tex]
substituting value
[tex]Q = \frac{7.10 *10^3 * 0.193}{9*10^9}[/tex]
[tex]Q = 1.522*10^{-7} C[/tex]
The number of electron removed is mathematically evaluated as
[tex]N = \frac{Q}{e}[/tex]
Where e is the charge on one electron with value [tex]e = 1.6 *10^{-19} \ C[/tex]
substituting values
[tex]N = \frac{1.522 *10^{-7}}{1.60*10^{-19}}[/tex]
[tex]N = 9.513 *10^{11}[/tex]
