Respuesta :

Answer:

It is E and F

Step-by-step explanation:

A quadratic equation is written in the form of ax²+bx+c. The two values of x that are the roots of the polynomial are E and F.

What is a quadratic equation?

A quadratic equation is an equation whose leading coefficient is of second degree also the equation has only one unknown while it has 3 unknown numbers. It is written in the form of ax²+bx+c.

The roots of the quadratic equation are found as shown below,

[tex]x = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}[/tex]

If the given equation x²-11x+17 is compared with the general quadratic equation ax²+bx+c, then the value of a, b, and c is 1, -11, and 17, respectively.

The roots of the given polynomial x²-11x+17=0 can be found as shown below. Therefore, The roots of the polynomial are,

[tex]x = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}\\x = \dfrac{-(-11) \pm \sqrt{(-11)^2 - 4(1)(17)}}{2(1)}\\\\x = \dfrac{11 \pm \sqrt{121 - 68}}{2}\\\\x = \dfrac{11 \pm \sqrt{53}}{2}[/tex]

x= (11 + √53)/2 , (11 - √53)/2

Hence, the two values of x that are the roots of the polynomial are E and F.

Learn more about Quadratic Equations:

https://brainly.com/question/2263981

#SPJ5