hevin9251
contestada

One circle has a diameter of 10 inches. A second circle has a diameter that is twice the diameter of the first circle. What is the ratio of the area of the smaller circle to the larger circle?

Respuesta :

09pqr4sT

Answer:

[tex]78.54:314.16[/tex]

Step-by-step explanation:

First circle area with diameter 10 inches =

[tex]\pi r^2[/tex]

[tex]\pi \times 5^2[/tex]

[tex]=78.53981[/tex]

Second circle area with diameter 20 inches =

[tex]\pi r^2[/tex]

[tex]\pi \times 10^2[/tex]

[tex]=314.159265[/tex]

[tex]78.53981:314.159265[/tex]

ujalakhan18

Answer:

78.5 : 314.2

Step-by-step explanation:

Diameter of the first Circle = 10 inches

Diameter of the second Circle = 2(10) [TWICE] = 20 inches

So,

Area of the first circle:

Radius = 5 inches

Area = πr²

A = (3.14)(5)²

A = 78.5 inches²

Area of the second circle:

Radius = 10 inches

Area = πr²

Area = (3.14)(10)²

Area = 314. 2 inches

Now the ratio of the area of smaller circle to the larger circle is

78.5 : 314.2

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