The equation of the rational function is: [tex]f(x) = \frac{-3(x + 4)(x -2)}{x^2-1}[/tex]
The x-intercepts of the rational function are given as: -4 and 2.
This means that, the zeroes of the function are (x + 4) and (x -2)
Multiply the zeroes of the function
[tex]f(x) = (x + 4)(x -2)[/tex]
The vertical asymptotes of the rational function are given as: 1 and -1.
This means that, the denominator is the product of (x + 1) and (x -1)
So, we have:
[tex]f(x) = \frac{(x + 4)(x -2)}{(x + 1)(x-1)}[/tex]
Express the denominator as the difference of two squares
[tex]f(x) = \frac{(x + 4)(x -2)}{x^2-1}[/tex]
Lastly, the horizontal asymptote is given as y = -3.
So, the actual function is:
[tex]f(x) = y \times \frac{(x + 4)(x -2)}{x^2-1}[/tex]
Substitute -3 for x
[tex]f(x) = -3 \times \frac{(x + 4)(x -2)}{x^2-1}[/tex]
This gives
[tex]f(x) = \frac{-3(x + 4)(x -2)}{x^2-1}[/tex]
Hence, the equation of the rational function is: [tex]f(x) = \frac{-3(x + 4)(x -2)}{x^2-1}[/tex]
Read more about rational functions at:
https://brainly.com/question/1851758
