Stereo speakers are manufactured with a probability of 0.100.10 being defective. TwentyTwenty speakers are randomly selected. Let the random variable X be defined as the number of defective speakers. Find the expected value and the standard deviation.

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Answer:

The expected value of X is 2 with a standard deviation of 1.34.

Step-by-step explanation:

For each speaker, there are only two possible outcomes. Either it is defective, or it is not. The probability of a speaker being defective is independent of other speakers. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

The expected value of the binomial distribution is:

[tex]E(X) = np[/tex]

The standard deviation of the binomial distribution is:

[tex]\sqrt{V(X)} = \sqrt{np(1-p)}[/tex]

Stereo speakers are manufactured with a probability of 0.1 of being defective

This means that [tex]p = 0.1[/tex]

Twenty speakers are randomly selected.

This means that [tex]n = 20[/tex]

Let the random variable X be defined as the number of defective speakers. Find the expected value and the standard deviation.

[tex]E(X) = np = 20*0.1 = 2[/tex]

[tex]\sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{20*0.1*0.9} = 1.34[/tex]

The expected value of X is 2 with a standard deviation of 1.34.