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If you add the digits in a two-digit number and multiply the sum by 7, you get the original number. If you reverse the digits in the two-digit
number, the new number is 18 more than the sum of its two digits. What is the original number?
O A 42
B. 24
C. 64
D.46
E.36

Respuesta :

gilbertazavedo72

Answer: A - 42

Step-by-step explanation:

Let x= ones digit, y=tens digit

1st (original number) :

7(x+y)=10y + x

2nd (new number by reversing the digits): 18+x+y=10x+y

simplifying:

1st condition: 6x=3y

2nd condition: x=2

substituting x=2 to 6x=3y

y=4

Answer:

The answer is 42 but let me tell you this question made my brain cell work an all nighter from how bad I am at riddles LOL

Step-by-step explanation:

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