Respuesta :
Answer:
The mean number of bags that arrive on time to its intended destination is 1260 with a standard deviation of 21.59.
Step-by-step explanation:
For each bag, there are only two possible outcomes. Either it arrives on time to it's intended destination, or it does not. The probability of a bag arriving on time is independent of other bags. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
Probability of exactly x sucesses on n repeated trials, with p probability.
The expected value of the binomial distribution is:
[tex]E(X) = np[/tex]
The standard deviation of the binomial distribution is:
[tex]\sqrt{V(X)} = \sqrt{np(1-p)}[/tex]
Luggage checked-in at Airline A arrives on time to its intended destination with a probability of 0.63.
This means that [tex]p = 0.63[/tex]
In a random sample of 2000 bags
This means that [tex]n = 2000[/tex]
Mean and standard deviation of the number of bags that arrive on time to its intended destination:
[tex]E(X) = np = 2000*0.63 = 1260[/tex]
[tex]\sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{2000*0.63*0.37} = 21.59[/tex]
The mean number of bags that arrive on time to its intended destination is 1260 with a standard deviation of 21.59.
