Answer:
the water level drop per hour is [tex]\frac{1}{26}\,\,\frac{in}{h} \approx 0.03846\,\,\frac{in}{h}[/tex]
Step-by-step explanation:
Notice that in between 11 PM and 8:45 AM on the following day, there is a change in time equal to 9 hours and 45 minutes = 9.75 hours.
If the water level of the pool dropped by 3/8 of an inch, and the rate was constant, then the rate of level drop per hour is:
[tex]\frac{\frac{3}{8} in}{9.75\,h} =\frac{1}{26}\,\,\frac{in}{h} = 0.03846\,\,\frac{in}{h}[/tex]
