Answer:
y = [tex]\frac{4\sqrt{3} }{3}[/tex]
Step-by-step explanation:
We are working with 30-60-90 triangles, and to solve for y we need to know the hypotenuse of the smaller triangle.
You can get that by finding the smaller value of the larger triangle.
[tex]\frac{8}{\sqrt{3} } =\frac{x}{1}[/tex]
x[tex]\sqrt{3}[/tex] = 8
x = [tex]\frac{8}{\sqrt{3} }[/tex]
x = [tex]\frac{8\sqrt{3} }{3}[/tex]
That is the hypotenuse of the smaller triangle. To find y...
[tex]\frac{(\frac{8\sqrt{3} }{3}) }{2} =\frac{y}{1}[/tex]
2y = [tex]\frac{8\sqrt{3} }{3}[/tex]
y = [tex]\frac{4\sqrt{3} }{3}[/tex]
Hope this helps!
