Respuesta :
Answer:
The probability that a randomly selected member of this class of homeowners will not file a claim of either type is 0.89.
Step-by-step explanation:
Denote the events as follows:
X = liability claim will be filled
Y = property claim will be filled
The information provided is:
P (X) = 0.04
P (Y) = 0.10
P (X ∩ Y') = 0.01
The probability that a randomly selected member of the class of homeowners will not file a claim of either type will be given by:
[tex]P[(X\cup Y)']=1-P(X\cup Y)=1-[P(X)+P(Y)-P(X\cap Y)][/tex]
According to the law of total probability:
[tex]P(B)=P(B\cap A)+P(B\cap A')[/tex]
Use the law of total probability to determine the value of P (X ∩ Y) as follows:
[tex]P(X)=P(X\cap Y)+P(X\cap Y')\\\\P(X\cap Y)=P(X)-P(X\cap Y')\\\\=0.04-0.01\\\\=0.03[/tex]
The value of P (X ∩ Y) is 0.03.
Compute the value of P (X ∪ Y) as follows:
[tex]P[(X\cup Y)']=1-P(X\cup Y)[/tex]
[tex]=1-[P(X)+P(Y)-P(X\cap Y)]\\\\=1-[0.04+0.10-0.03]\\\\=1-0.11\\\\=0.89[/tex]
Thus, the probability that a randomly selected member of this class of homeowners will not file a claim of either type is 0.89.
