Respuesta :

Answer:

(4x^2 +9)(4x^2-9) =0

Step-by-step explanation:

16x^4 - 18 = 0

Rewriting

(4x^2)^2 - 9^2 =0

We notice that this is the difference of squares

a^2 - b^2 = (a-b)(a+b)

(4x^2 -9)(4x^2+9) =0

Answer:

The answer is option 2.

Step-by-step explanation:

In the question, 16 and 81 are perfect squares. So in order to find the equivalent equation, you have to factorize it :

APPLY,

[tex](a + b)(a - b) = {a}^{2} - {b}^{2} [/tex]

So for this question :

[tex]16 {x}^{4} - 81 = 0[/tex]

[tex]{(4 {x}^{2})}^{2} - {(9)}^{2}= 0[/tex]

[tex](4 {x}^{2} + 9)(4 {x}^{2} - 9) = 0[/tex]